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Juan attends a carnival. The admission fee is $8. Tickets for the rides cost $4 each. Juan needs one ticket for each ride. Write an equation Juan can use to determine the number of ride tickets r, he can buy if he has $32 before he pays the admission fee. (That the question)
This is the same one but just different to it
Using the equation above, find the number of tickets Juan can buy.
(can you guys show your work that would be really helpful)
5 Answers
- 1 decade agoFavorite Answer
Juan has $32. The entrance fee is $8. Subtract $8 from $32:
$32 - 8 = $24
Now he needs tickets, each for $4. So you divide $24 by $4, equaling 6:
$24 / $4 = 6
So in an equation format, it would be:
($32 - $8) / $4 =
$24/$4= 6
So in total, he can by 6 tickets.
- Anonymous1 decade ago
To be simple.
4x=32-8
4x=24
Now divide boths side by 4 and you get.
x=6 rides.
- 1 decade ago
write an equation:
32=4r+8
subtract 8 from 32
24=4r
divide 24 by 4
r=6
hope i helped
:D
- 1 decade ago
You first have to set up an algebraic equation for this:
amount of money Juan has = admission fee + cost per ride * no. of rides
This equation will allow you to relate the amount of money Juan has, and then solve for the no. of rides he is able to go on.
You can re-write this equation using variable, allowing for r to be the no. of rides that Juan goes on, and then solving for r.
Thus;
$32 = $8 + $4r
subtract $8 from both sides of the equations
$32 - $8 = $8 - $8 +$4r
$ 24 = $4r
divide both sides by 4, and you will get r = 6. Thus, the number of rides Juan can go on is 6.
Source(s): Not a site, but a great book - Mastering Mathematics VII