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integer problem to find how many numbers you can find?
How many positive three-digit integers are there such that each digit is an odd number less than 6?
3 Answers
- 1 decade agoFavorite Answer
135
153
315
351
513
531
6 if you can only use each number once
111
113
115
131
133
135
151
153
155
311
313
315
331
333
335
351
353
355
511
513
515
531
533
535
551
553
555
27 with that one. Hope that helps!
- fcas80Lv 71 decade ago
The first digit can be done in 3 ways: 1, 3, or 5. For each way the first digit is done, there are 3 ways to make the second digit. For each way the the first and second digit is done, there are 3 ways to make the third digit.
27 = 3 * 3 * 3
- ?Lv 44 years ago
purely a guideline, i will artwork on it later (sorry, I easily have a headache now) , yet have you ever tried mathematical induction? EDIT: ok, except I made a mistake I easily have confirmed the inequality making use of mathematical induction however the answer is amazingly long to jot down right here. perhaps i did no longer see an much less demanding way, yet interior my inequality, i chanced on I got here across yet another inequality which I used yet another application of mathematical induction in. attempt mathematical induction in case you like. i will see if i will use cheeser's suggestion. i'm particular that some sensible human beings available would have a extra stylish answer than the only I did.
