Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Find The constant c that makes g continuous on (-∞, ∞)?
Find The constant c that makes g continuous on (-∞, ∞)
g(x)= x^2-c^2 if x < 4
cx+20 if x >=4 (that's less than or equal to)
3 Answers
- Anonymous1 decade agoFavorite Answer
16 - c^2 = 4c + 20
c^2 + 4c + 4 = 0
(c+2)^2 = 0
c+2 = 0
c = -2
********************
- ?Lv 45 years ago
the only ingredient g(x) ought to be probably discontinuous is x = 4. If g(x) *is* non-supply up there, then: x² - c² = cx + 20. So, placing x = 4, provides: sixteen - c² = 4c + 20; or, after rearranging, c² + 4c + 4 = 0. After somewhat concept, this incredibly factors into: (c + 2)(c + 2) = 0, the only actual answer to this being, c = ? is smart? ~Soylent Yellow
