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Physics!!!!!!!!!! Help me!!!!!!!!!!!!!!!!?
A small fish is dropped by a pelican that is rising steadily at .50 m/s.
After 2.5 seconds, what is the velocity of the fish?
2 Answers
- anil bakshiLv 71 decade agoFavorite Answer
pelican and fish both had u = + 0.50 m/s upwards
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it is as if pelican threw fish downwards at
u1 = - 0.50 m/s
t = 2.5 s
v(later) = u1 + gt
= - 0.50 + 9.8*2.5
= 24 m/s
- 1 decade ago
Ignoring wind resistance and assuming the pelican's ONLY velocity is vertical rising (very odd)...
x''=-9.8
x'=-9.8*t+.5
x'(2.5)= -24 m/s or 24 m/s downwards
