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Trigonometric Functions....help please?
I already did the problems, i just want to check to see if i did them right...
1) If sin(-t) = 2/5, find sin t and csc t.
my answer: sin t = 2/5, csc t = 5/2
2) If cos t = -3/4, find cos (-t), and sec (-t)
my answer: cos(-t)= -3/4, sec(-t) = -4/3
If cos t = 4/5, find cos (pi - t) and cos (t + pi)
my answer: pi/5, 9pi/5
I'm pretty sure some of these are wrong....can someone help me out pleeeease and thanks???
1 Answer
- Anonymous1 decade agoFavorite Answer
1.
sin(- t) = - sin(t)
csc(t) = 1 / sin(t)
You have the right numerical values, but the wrong sign for both sin(t) and csc(t).
2.
cos(- t) = cos(t)
sec(t) = 1 / cos(t)
Again, the right numerical values, but the wrong sign for both answers.
3.
cos(pi - t) = - cos(t)
cos(pi + t) = - cos(t)
There is no pi in the answers here. They are just a straight sign change from 4 / 5 to - 4 / 5.
Refer to the graphs of cos(x) and sin(x) on this page: