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Calc Help! Related Rates Homework?
I'm having trouble figuring out this problem on my calc homework.. please help!
The area of a cone is 1/3*pi*r^2*h. The height and radius of the cone increase at a constant rate of 1/2 when r=9 and h=6. How fast is volume changing?
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- fireFoxLv 61 decade agoFavorite Answer
v = 1/3*pi*r^2*h
dv/dt = 1/3*pi*(2r*h*dr/dt + r^2*dh/dt)
dv/dt = 1/3*pi*(2*9*6*1/2 + 9^2*1/2)
dv/dt = 98.96
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