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Calculate the speed of a 110 kg person at the equator?
Early skeptics of the idea of a rotating Earth said that the fast spin of Earth would throw people at the equator into space. The radius of Earth is about 6400 km. Show why this objection is wrong by determining the following information.
(a) Calculate the speed of a 110 kg person at the equator.
__ m/s
(b) Calculate the force needed to accelerate the person in the circle.
__ N
(c) Calculate the weight of the person.
__ N
(d) Calculate the normal force of Earth on the person, that is, the person's apparent weight.
__ N
1 Answer
- PhysicsDudeLv 71 decade agoFavorite Answer
(a) v = ωr = (2π/T)r = 2(3.14)(6.4 x 10^6) / (24 x 60 x 60) = 465.42 m/s
(b) F = mv²/r = (110)(465.42)² / (6.4 x 10^6) = 3.72 N
(c) W = mg = (110)(9.81) = 1079 N
(d) N = W = 1079 N
