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You pull your 18 kg suitcase at constant speed on a horizontal floor by...?
You pull your 18 kg suitcase at constant speed on a horizontal floor by exerting a 41 N force on the handle, which makes an angle θ with the horizontal. The force of friction on the suitcase is 30 N.
(a) What angle does the handle make with the horizontal?
__°
(b) What is the normal force on the suitcase?
Magnitude
__ N
(c) What is the coefficient of friction?
___
2 Answers
- 1 decade agoFavorite Answer
Using F = ma
Since the system is at constant speed, F(net) = 0
taking horizontal motion
F - f = ma
F - f = 0
41 cos @ - 30 = 0
cos @ = 30 over 41
@ = arch cos 30/41
= ANSWER1
Taking vertical motion
Normal force on the suitcase,
R = mg - 41 sin @
= 18(9.81) - 41 sin @
= ANSWER2
Friction, f = uR
= u ANSWER2
u = f over ANSWER2
= ANSWER3
Source(s): www.youtube.com/thephysicsidiot - Anonymous5 years ago
Draw a Free Body Diagram, list all of the forces horizontally and vertically. I will define forces going in the east and north direction as positive and forces going in the west and south direction as negative Fy = N - mg + Fsin(angle) = ma = 0 (The suitcase is not accelerating in the vertical direction) N = mg - Fsin(angle)
