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MATH helpp please! On 3 Dimensionall Shapess!?
A sqaure pyramid is divided into 3. I need to calculate the volume and the surface area of the regular sqaure pyramids with the following dimensions.
The first regular pyramid gives you 2 informations.:
The base -= 6m the height: 4m
I need to figure out the surface area and the volume.
The second regular pyramid gives you 2 informations: The slant height is 13m and the height is 12m .
the third regular pyramin gives you the perimiter which is 16m and the height which is 5m ...
- i need to figure out the Surface area and volume of all these shapes.
How to find the surface Area:
Ab+Al
AL= Area of Lateral
Ab= Area of Base. (Area of base) + (Area of Lateral)
To find the area of a Lateral you do PbXSh.
Pb= Perimiter of Base
Sh= Slant Height,
To find the area of the base you do Sl X Sl.
Sl= Side length.
**PLEASE SHOW ALL WORK...
--My problem was they didnt give you the slant height or wtv for some of the shapes and i couldnt figure it outtt. :(
HELP...
1 Answer
- 1 decade agoFavorite Answer
To find the slant height, use the Pythagorean Theorem (a^2 + b^2 = c^2)
Example:
If the base of a lateral side is 6 un. and the side length is 5 un, then the slant height would be the altitude of a right triangle with a base of 3 un. (1/2 the base length of the lateral side) and a hypotenuse of 5 un.:
a =slant height
b = 3 (1/2 lateral base)
c = 5 (side length)
a^2 + b^2 = c^2
a^2 + 3^2 = 5^2
a^2 + 9 = 25
a^2 =16----------------------> Find the square root of both sides to solve for "a"
a = 4
The slant height is 4 units.
You should now be able to do the rest of your assignment since you seem to have all the information you need now. Good luck!
