Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Physics of Motorcycle DynaBeads?
Please explain, using forces, inertia, etc.
"They move to balance the rotation of the tire" doesn't do it for me. What forces inside the tire motivate the beads to move to the correct location to balance the tire?
Unfortunately, the Wikipedia article concerns the history and chemical uses, not the physics of tire balancing.
2 Answers
- 5 years ago
Just figure out how much work is done by the motorcycle in 1 second and that will be your power, since Power = Work done per second. a) In one second the work done by the motorcycle in overcoming resistance is 160 N times 16 meters = 2560 J since work = force x distance. So Power is 2560 J/s or 2560 Watts. b) For this figure out how much it rises in 1 second and add that potential energy to the work found in part a). That will be J/s so that is the final answer in watts. (it rises 16 meters * sin 45 so just use that for h in mgh). c) Energy = Power times time or 2560 Watts x 60*60*3. Whatever that is in joules.