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- 1 decade agoFavorite Answer
Dividing by a number is the same as multiplying by the reciprocal(sp?).
[(a^2-b^2)/(3a+3b)]x[(9)/(a-b)^2]
Then foil the bottom.
[(a^2-b^2)/(3a+3b)]x[9/(a^2-2ab+b^2)
Then times the top numbers together and the bottom two together (by foiling).
(9a^2-9b^2)/(3a^3-6a^2b+3ab^2+3a^2b-6ab^2+3b^3)
Then add like terms.
(9a^2-9b^2)/(3a^3-3a^2b-3ab^2+3b^3)
You can't simplify any more.
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