c++ looping through a array test condition (10 points)?

Question

void IntegerSet::printSet()
{
int i, count=0;
for(i=0;i<SIZE;i++)

if(a[i]==1)
{
count++;
cout<<i<<" ";
}

if(count==0)
cout<<"---";
 }



I need to add some code to the print function I have defined so that only 20 elements show up on each line...... I understand I need something like if count = 20  cout<<endl; but by adding an if in the middle, it does nothing.... this condition I got now works great, prints everything as expected, just need a little assistance thanks........

oops · Accepted Answer

for(int i=0; i<SIZE; i++)
{
    if(a[i]==1)
    {
        if(count % 20 == 0)
            cout << endl;
        count++;
        cout << i << " ";
    }
}

Walkalone · Answer

All you need is "only 20 elements show up on each line"?
So did you put 
 if (count==20)
 {
    cout<<endl; 
    count ++;
 }
and 
 if(a[i]==1)
 {
   count++;
   cout<<i<<" ";
 }

into this {  } right after for(i=0;i<SIZE;i++) ?
That is what i understand tho.
Good luck!

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c++ looping through a array test condition (10 points)?

2 Answers