overloading operators in c++?

Question

is this correct way to do it?

class Time
{
public:
         bool Time::operator ==(const Time &other) const
 friend std::ostream& operator<<(ostream&, Time&);
private:
    int hour;
    int minute;
};

   bool Time::operator==(const Time &other) const {
    return !(*this == other);
  }
ostream& operator<<(ostream &out, Time &ob) {
out << “Time : ”<<ob.hour << ob.minute<<endl;
return out; }

oops · Accepted Answer

Close.  You've got the signature right, but you've defined the function in terms of itself.  This expression:

*this == other

Is calling operator== of the the Time class.  So what you've actually done there is create a recursive function with no terminating condition.  What you want to do is this:

bool Time::operator==(const Time &other) const {
    return ((hour == other.hour) && (minute == other.minute));
}

Your output operator will work, but the Time object should be const.

Lastly, in your class body, you don't need to prefix your operator function with "Time::", you can just write it like this:

bool operator ==(const Time &other) const;

bichoff · Answer

Operator overloading is under polymorphism a particular function in C++. together as the operators in C have nicely-known meaning operator overloading in C++ enables us to overload the operator to offer the specific consumer defined function to the operator. Syntax is going like this operator x(arguments) { function } the place x is an operator operator overloading is as a rule used to function the products making use of operators quite of working their contributors.

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overloading operators in c++?

2 Answers