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I know i ask a lot of physics questions, one more tonight?
A clerk moves a box of cans down an aisle by pulling on a strap attached to the box. The clerk pulls with a force of 177.0 N at an angle of 34° with the horizontal. The box has a mass of 35 kg, and the coefficient of kinetic friction between the box and the floor is 0.45. Find the acceleration of the box.
FYI, I am working on this problem right now and I can't get it correct, so I don't just post my hw on here so that other people will do it for me, I just need help.
2 Answers
- helloLv 61 decade agoFavorite Answer
Force friction = mu x Force normal
Force applied horizontally = 177.0 cos34 deg subtract the friction force = ma = 35 a
Force normal + Force applied ( sin34) = mg = 35 (9.8)
Force normal = 35(9.8) - 177.0 sin(34) work it out
Then find friction force.
Then solve for a
- Anonymous1 decade ago
Do it yourself you lazy bum.
