c++ questions, converting string to int?

There are many options (as with everything in C++)

1. Use the standard conversion function stoi() (requires recent C++ compiler, such as MSVC 2010 or gcc 4.4)

#include <string>

#include <iostream>

int main()

{

     std::string s = "1234";

     int i = stoi(s);

     std::cout << "integer is " << i << '\n';

}

2) use the C library conversion function atoi() (it has poor error handling in case conversion fails, though)

#include <string>

#include <iostream>

#include <cstdlib>

int main()

{

     std::string s = "1234";

     int i = atoi(s.c_str());

     std::cout << "integer is " << i << '\n';

}

3) use operator>> from a string stream:

#include <string>

#include <iostream>

#include <sstream>

int main()

{

     std::string s = "1234";

     std::istringstream is(s);

     int i;

     is >> i;

     std::cout << "integer is " << i << '\n';

}

4) use lexical_cast from the boost library (www.boost.org) which will automatically use one of the above three methods or whatever else is more efficient on your platform

#include <string>

#include <iostream>

#include <boost/lexical_cast.hpp>

int main()

{

     std::string s = "1234";

     int i = boost::lexical_cast<int>(s);

     std::cout << "integer is " << i << '\n';

}

C Parse Int

U have to parse the String to int....

use parseInt() function for that

ie. int z=parseInt(x);

if it doen't work try Integer.ParseInt()

i just confused with VB and c++ at this time..

or just refer books to parse string as int or google it.

include <sstream>

#include <string>

using namespace std;

// string to int

string some_string;

istringstream buffer(some_string);

int some_int;

buffer >> some_int;

// int to string

int some_int;

ostringstream buffer;

buffer << some_int;

string some_string = buffer.str();