What is the formula for capillary action?

Height raised in capillary, h = [2S(cosA)]/[rρg]

--where S is surface tension, A is the contact angle , r is the radius of capillary , ρ is the density of liquid and g is acceleration due to gravity

For a water-filled glass tube in air at standard laboratory conditions, S = 0.0728 N/m at 20 °C, A = 20° (0.35 rad), ρ is 1000 kg/m3, and g = 9.8 m/s2. For these values, the height of the water column is

h ~ (1.45^10-5)/r m

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If a capillary tube has radius 'r' is dipped into a liquid of surface tension 'γ' Then within the tube, the air pressure will be 'P(air)' and the rising liquid pressure, just below the meniscus, will be P(liquid). The pressure difference is given by: - P(air) - P(liquid) = 2γ/r If 'h' denotes the distance of capillary rise and 'ρ' is the liquid's density, then: - P(air) + (P(liquid) - P(air)) + hρg = P(air) Thus, at the pressure balance height: - hρg - 2γ/r = 0 Or, the height of rise is: - h = 2γ/(rρg) However, I am not certain that a syphon effect can take place due to capillary action alone! I hope this is of some assistance!