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How much heat is absorbed when 24.8 grams of H2O (Liquid) at 10 degrees Celsius is converted to Steam at 100 degrees Celsius. I am not confident in my steps of work because I have to put it in dimensional anaylsis.
1 Answer
- HPVLv 71 decade agoFavorite Answer
There are two steps: (1) heating the water from 10 C to 100 C, (2) vaporizing the liquid H2O to gaseous H2O.
Step 1: heat required = (mass H2O)(sp. ht. H2O)(Tf - Ti) = (24.8 g)(1.00 cal/g C)(100C - 10C) = 2230 cal
Step 2: heat required = (mass H2O)(heat of vaporization H2O) = (24.8 g)(540 cal/g) = 13,400 cal
Total heat required = 2230 cal + 13400 cal = 15,600 cal = 15.6 kcal
