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Calculating angular velocity and acceleration of planet Io?
Io information:
Orbital Radius: 42180 km (42180000 m)
Radius: 1821 km (1821000 m)
Year: 11.84 days (1022976 s)
Length of Day: 9 hr 50 min (35400 s)
What is the angular velocity of Io? And what is the angular acceleration needed to stop Io from spinning in 10 earth years [exclude leap years, use just 365 days].
Please show calculations and work. Thanks!
Ack typo, sorry Io isn't a planet
And also, what is the acceleration due to gravity on Io's surface?
1 Answer
- SteveLv 79 years agoFavorite Answer
Angular velocity about polar axis of Io:
w = 2π/T = 2π/35400 = 1.77491E-4 rad/sec
α = dw/dt = -1.77491E-4/(10*365*24*3600) = -5.6282E-13 rad/sec²
The orbital angular velocity Ω = 2π/1022976 = 6.142E-6 rad/sec, which when added to w gives w' = 1.836E-4 rad/sec (the w as seen from a great distance). This increases the value of α by a factor of 1.0346. [All this assumes the orbital and rotational angular velocity have the same sign}
For gi, I had to look up the mass of Io, m = 8.9319E22 kg:
then,
gi = G*m/R² = 6.67E-11*8.9319E22/(182100)²
gi = 1.7966 m/sec²
This is about what I remember from the last time I was there......
Source(s): Eqs of SHM and constant acceleration Newton