I have a math problem.. Could I get some help?

(x+3)(x-3) / (x^2+x-21)

The x-intercepts are where y=0.

This will happen when the numerator is 0; you missed one.

You got the y-intercept correct.

The horizontal asymptote is dominated by the highest degrees in the numerator and denominator, which yield x^2/x^2 = 1. Good work.

I have no idea how you got y=1 for a vertical asymptote. These would be where the denominator is 0. Plugging those numbers into the quadratic equation gives you

(-1 +- sqrt(1 + 4*21)) / 2

I don't see how you got a simple "1" out of that.

Now, if that's a typo, and it's supposed to be x^2+x-2, then y=1 is, indeed, *one* vertical asymptote. Use that to factor the denominator, and you'll see the other solution in the remaining factor.

Also, I do not see how you get a domain of two points, or even an interval with those two points. What *does* restrict the value of x? Those are the points that you exclude from the domain.

Finally, for the sign pattern, you need to track the function's value across all the sign changes of the factors. Once you've factored both quadratics, this becomes relatively easy: take one point between each pair of zeros and one off each end. For instance, use -4 and 4 for the "off the ends" x values. Use 0, -2, and/or half-values for the in-betweens. Those will give you the signs of each factor, which you can use to get the sign changes of the function. I expect that you'll get four sign changes rather than two, such as +-+-+.

Does that get you going?

three. 80x four. 80x + a million five. 250(80x + a million) 6. 250(80x + a million) + y 7. 250(80x + a million) + 2y eight. 250(80x + a million) + 2y - 250 nine. [250(80x + a million) + 2y - 250] / two = [20000x + 250 + 2y - 250] / two = [20000x + 2y] / two = 10000x + y

it's new years eve and you are doing maths :o jks i came on to check who is doing the same as me, sorry man i'm unfarmilliar with this question, it would help if you told me what year mathematics you were doing and what level