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***10 points*** Chem help?
Common Ion
At some other temperature, a solid sample of Ca(OH)2 is shaken with 0.0100 M CaCl2.
Once equilibrated, some solid Ca(OH)2 remains undissolved.
The solution is filtered and a 15.00 mL sample requires 20.64 mL of 0.0100 M HCl to neutralize it.
Calculate the value for Ksp of Ca(OH)2 from this data.
I found Ksp = 3.20×10-6
What is the molarity of Ca(OH)2 which is dissolved in this solution?
I found 6.88×10-3 M
What is the solubility of Ca(OH)2 in this solution, in g/100mL?
g/100mL
I can't get part c... I'm so frustrated. If someone could show me how to find the solubility I would really appreciate it. Thank you in advance.
1 Answer
- Mark S, JPAALv 79 years agoFavorite Answer
I think you just take the molarity and convert it to grams/L, then divide by 10 since you have 100 mL.