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find the normal approximation for the binomial probability that x=5, where n-12 and p=0.7.?
find the normal approximation for the binomial probability that x=5, where n=12 and p=0.7. compare this probability to the value of p(x=5) found in table 2 of appendix B
1 Answer
- GuyLv 79 years agoFavorite Answer
I assume you meant n=12, not n-12?
The normal approximation to the binomial would use a mean of
u = 0.7*12 = 8.4
and a standard deviation of
sigma = sqrt(12 * 0.7 * 0.3) = 1.58745
The normal approximation for p(x=5) would be:
P(4.5 < x < 5.5)
= P((4.5 - 8.4)/1.58745 < z < (5.5 - 8.4)/1.58745)
= P(-2.46 < z < -1.83)
= .0267
The probability in the binomial table is .0291.