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Help in a trigonometric equation?
Give the value of x in the trigonometric equation:
cos^2 x + cot 2x = (1/2)
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- ?Lv 79 years agoFavorite Answer
cos^2x+cot 2x=0.5=>
(1+cos2x)/2+cos2x/sin2x=0.5=>
(cos2x+2cos2x)/(2sin2x)=0=>
3cos2x=0=>
cos2x=0=>
2x=2npi+/-(pi/2)=>
x=npi+/-(pi/4)=>
x=(4n+/-1)pi/4
where n=0,1,2,3,...
For 0=<x<=2pi
x=pi/4, 3pi/4, 5pi/4, 7pi/4.
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