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Higher Maths Straight Line Help?
Question: A straight line has equation 2x + y - 3 = 0. If the point (k,-1) lies on this line, find the value of k.
I know how to do this question if I am given coordinates of points on the line but I am unsure how to do this question when given the equation of the line. Can someone please talk me through how I would answer this question?
2 Answers
- 9 years agoFavorite Answer
If k,-1 lies on the line, then if k were x, -1 would be y.
Therefore if y=-1, x=k
putting y=-1 into the equation gives 2x-1-3=0
x=2, k=2
- ?Lv 44 years ago
The slope of the provide line is (-4) . for this reason the slope of the line perpendicular to this would be( utilising the valuables m1*m2 = -a million) = +a million/4 the needed equation would be y = (a million/4)x + c because of the fact the line passes by using (-a million,3), substituting those values of x and y interior the needed equation 3 = (a million/4)*-a million + c implies c = 3 + a million/4 = thirteen/4. the needed equation of the line is y = (a million/4)x + thirteen/4
