Higher Maths Question Help?

Right, you need to find a coordinate and the gradient, which can be found from the gradient. So:

2x + y - 3 = 0

Now, if you want a coordinate and gradient you need to rearrange the equation into the form:

y = mx + c

So, to do that, take of 2x and add 3 to get:

y = -2x + 3

Now you know that gradient is -2 and the y intercept is at (0,3)

Now, you know the gradient, a coordinate, and part of a coordinate. So, the gradient formula is:

M = y2 - y1

,,,,, ----------

,,,,, x2 - x1

(0,3) (k, -1)

You can substitute what you know into this equation to get k. So:

-2 = -1 - 3

,,,,,, ---------

,,,,,, k - 0

So:

-2 = -4/k

-2k = -4

k = 2

Hope that helps!

You just plug in when x=k , y = -1

so 2k + (-1) -3 = 0

2k -4 =0

2k=4

k=2

2k + (-1) -3 = 0

2k -4 =0

2k=4

k=2