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Deriving e^(x^2+y^2)?
How would I approach this derivation? I'm supposed to derive it with respect to both x and y.
1 Answer
- 8 years agoFavorite Answer
Depends. If you are finding df/dx, then you are derivativing it with respect to x. If you are finding df/dy, then you are derivativing it with respect to y. If you are talking about parital derivatives, then you do two separate calculations: one to find df/dx (where d is really curvy) and df/dy (again d is curvy).
If its partial derivatives, then df/dx = 2x e^(x^2 + y^2) and df/dy = 2y e^(x^2 + y^2)
If its not partial derivatives and you want to find df/dx, then
df/dx = (2x + 2y dy/dx) e^(x^2 + y^2)
If its not partial derivatives and you want to find df/dy, then
df/dy = (2x dx/dy + 2y) e^(x^2 + y^2)