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sparky34
sparky34 asked in Science & MathematicsMathematics · 8 years ago

Can some one explain this limit to me? Calculus.?

lim x->-2 (x^4-4x-24)/(x^3+x^2-x+2)

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  • Iggy Rocko
    Lv 7
    8 years ago
    Favorite Answer

    Since the numerator and denominator approach 0, use L'Hopital's rule and take the derivatives of the numerator and denominator.

    lim (x^4 - 4x - 24)/(x^3 + x^2 - x + 2) =

    x-> -2

    lim (4x^3 - 4)/(3x^2 + 2x - 1) = -36/7

    x-> -2

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