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lim x->0 (e^(2x^2)-1-2x^2)/(x^4)?
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- BrendaLv 78 years agoFavorite Answer
lim [e^(2x²)-1-2x²]/x^4
x->0
You may use L'Hopital's rule first as it is a 0/0 form.
lim [4x*e^(2x²)-4x]/4x^3
x->0
lim [e^(2x²)-1]/x²
x->0
Taking again we get:
lim [4x*e^(2x²)]/2x
x->0
lim 2e^(2x²)
x->0
As x->0 then 2e^(2*0²) = 2
The limit is 2.
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