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A asked in Science & MathematicsBiology · 8 years ago

Crossing AabbCcDd x AaBbCcdd?

What are the odds that the two parents would produce a girl with thick lips, no facial hair, rounded teeth and a square face?

A=thick lips

a=thin lips

B=excessive facial hair

b=no hair

C=pointy teeth

c=round teeth

D=oval face

d=square face

Update:

Its for a bio problem, you dolt

1 Answer

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  • Anonymous
    8 years ago
    Favorite Answer

    Treat each trait separately:-

    Thick lips - Aa x Aa = AA, Aa, Aa,aa = 3/4 thick lips

    No facial hair - Bb x bb = Bb, Bb, bb, bb = 2/4 no hair

    Rounded teeth - Cc x Cc = Cc, Cc, Cc, cc = 1/4 rounded teeth

    Square face - Dd x dd = Dd, Dd, dd, dd = 2/4 square face

    3/4 x 2/4 x 1/4 x 2/4 = 12/256 = 3/64 chances.

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