Anyone good at physics?

Newton is the S.I. unit of force and is denoted by the capital letter N.

N = kg*m/s^2

[mass (kg) multiplied by meters per second squared]

Newtons 2nd law of motion, F=ma [Force = mass times acceleration] is measured in Newtons (N)

In other words, to derive a newton you take a mass and apply an acceleration. The net force required to accelerate a mass of one kilogram at a rate of one meter per second squared = 1N (newton).

**Part Two**

Total Force is equal to the applied force [F(app.)] on the mass, minus the coefficient of friction (µ) times the mass of the object (m) times gravity (g).

F = F(app.) - µ(mg)

Given newtons 2nd law F=ma, replace the F on the left side with ma.

ma = F(app.) - µ(mg)

Solve for F(app.)

F(app.) = ma + µ(mg)

From here it is plug and chug!

F(app.) = 26kg * 1.3m/s^2 + 0.29 (26kg * 9.8m/s^2)

= 107.7N

a quantity has a a description, a unit name and a dimension

example length of a string unit feet, dimension length

pure number have no units 5 is a number , 5 apples is a number of apples

the basic dimensions are Mass, Length Time and Electric charge (or current)

acceleration has no unit name but is Meter/sec^2

Force is mass * acceleration unit kilogram*meter/sec^2

force name is Newton 1 newton = 1 kilogram* 1 meter/sec^2

( or 1 Klogram * 2 meter/sec^2 etc)

friction problems are more complicated the force is sideways but the friction is due to the DOWN weight and the co efficient of friction (approximately)

weight is newtons due to the mass and the local acceleration of gravity about 9.8 meter/sec^2

a newton is the unit of force in the MKS system

since F = ma and m is kg, a is m/s^2 you get newtons = kg m / s^2 in basic units

friction force = weight times coeff of friction = mg Cf

force to accelerate = m a = Fh - mgCf

so you have Fh = m (a + gCf) = 26kg (1.3 + 9.8 x .29)m/s^2

just complete the arithmetic to get your answer

By F(net) = F(applied) - f(friction)

=>ma = F - µ x N

=>ma = F - µ x mg

=>F = m(a+µg)

=>F = 26 x (1.3 + 0.29 x 9.8)

=>F = 107.69 Newton