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From the top of a tower of height 200 m, a ball A is projected up with 10 m/s and two seconds later another?
From the top of a tower of height 200 m, a ball A is projected up with 10 m/s and two seconds later
another ball B is projected vertically down with the same speed. Then :
(A) both A and B will reach the ground simultaneously
(B) the ball A will hit the ground 2 seconds later than B hitting the ground
(C) both the balls will hit the ground with the same velocity
(D) none of these
3 Answers
- TechnobuffLv 78 years agoFavorite Answer
Time for up ball to rise to max. height = (v/g) = 10/10, = 1sec.
Therefore at 2 secs.,it will be at the level from which it was thrown, and again will be doing 10m/sec.
So as the 2nd. ball is also going down with the same speed from the same position at the same time.
Both will reach the ground together. Ans = A.
Therefore ans. C is also true.
Source(s): g is not 10, but that's what you are expected to use, obviously. - ?Lv 58 years ago
A. and C
They start in the same position with the same speed and end in the same position with the same speed.
- Anonymous8 years ago
I want to use my 'LIFE LINE'
