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A baseball, 167 grams, is pitched at 50 m/s when is hit by the batter....?
A baseball, 167 grams, is pitched at 50 m/s when is hit by the batter. The ball travels in the opposite
direction it was thrown from with a speed of 70 m/s. What is the change in momentum of the baseball?
1 Answer
- Anonymous8 years agoFavorite Answer
We'll compare the momentum on the ball before, and after it is hit by the bat.
Remember to keep the units in kilograms, so the units make sense.
We'll say that the pitch is thrown in the positive direction, and the ball is hit in the negative direction.
Momentum of pitch:
p(pitch) = 0.167[kg] * 50 [m/s] = 8.35 [kgm/s]
Momentum of the Hit:
p(hit) = 0.167[kg] * -70[m/s] = -11.69 [kgm/s]
So, now we know the two momentum, let's find the change in this momentum.
We'll do, the final momentum minus the original momentum.
p(hit) - p(pitch) = -11.69[kgm/s] - 8.53[kgm/s] = 20.22[kgm/s] = change in momentum.