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Find two nonnegative numbers whose sum is 20 and such that the product of twice one?

and the square of the other number

will be a maximum.

10 and 10, right?

1 Answer

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  • ?
    Lv 7
    8 years ago
    Favorite Answer

    x= one non-neg number

    y= the other.

    Given: x + y = 20 ....... (1)

    .... 2xy^2 => Max ....... (2)

    From (1): ..... y= 20 - x

    (1) in (2)

    z = 2x ( 20 - x )^2 => Max

    z = 2x ( 400 - 40x + x^2 )

    z= 800x - 80x^2 + 2x^3 => Max

    Find dz/dx:

    dz/dx = 800 - 160x + 6x^2 = 0 ................ Divide by 2

    ........... 3x^2 - 80x + 400 = 0

    ...........( 3x - 20)( x - 20) = 0

    .............. x = 20/3 or x= 20 ................. x can not be 20 because y would be 0.

    Sub x = 20/3 in (1)

    ...... 20/3 + y = 20

    ................ y = 40/3

    The first number is 20/3 and the number squared is 40/ 3

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