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Impossible Physics 1 Problem!!?
A soccer ball is kicked with an initial speed of 10.3 m/s in a direction 25.7° above the horizontal.
1. Calculate the magnitude of its velocity 0.360 s after being kicked.
I got 9.33 m/s...this is correct
2. What was its direction?
I am not sure how to solve for direction
3. Calculate the magnitude of its velocity 0.720 s after being kicked.
9.64 m/s is correct
4. What was its angle relative to the horizontal (choose positive for above and negative for below)?
Not sure how to solve for this angle :(
1 Answer
- 8 years agoFavorite Answer
FIRST ENSURE YOUR CALCULATOR IS IN DEGREES MODE
The vertical component after 0.360s is
10.3*sin(25.7°) - 9.81*0.360 = 4.467 - 3.532 = +0.935 m/s (UP)
The horizontal component is 10.3*cos(25.7°) = 9.281 m/s (constant)
Now use R -> P on your calculator:
X=9.281, Y=0.935
1. => Magnitude is 9.33 m/s
2. => Angle is +5.75° (above horizontal)
The vertical component after 0.720s is
4.467 - 9.81*0.720 = –2.596 m/s (DOWN)
X=9.281, Y= –2.596
3. => Magnitude is 9.64 m/s
4. => Angle is –15.6° (below horizontal)
Angle can also be "manually" calculated as arctan(Y / X)
