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Finding the Height of a Wedge?
A small block of mass m1 = 0.5 kg is released from rest at the top of a curved wedge of mass 7.0 kg, which sits on a frictionless horizontal surfac. When the block leaves the wedge, its velocity is measured to be 4.8 m/s to the right, as in Figure P6.59b. (a) What is the velocity of the wedge after the block reaches the horizontal surface?
I found the answer to A) and it is -0.343 m/s
PART B) ... what is the height of the wedge?
I cannot figure out part B... I tried using
mgh= 1/2 mv^2 and I got a height of 1.7 meters... this is incorrect and I am clueless :(
Thanks in advance for the help! :D
1 Answer
- peterpanLv 78 years agoFavorite Answer
a)
m1v1=-m2v2
v2=-v1m1/m2
v2=-0.34 m/s
b)
m1gh=1/2m1v1^2+1/2m2v2^2
h=(v1^2+v2^2)/(2m1g)
h=2.36 m