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Solve the following logarithmic equation.?
log (x-5) + log (x+2) = log (x+3)
Round off answer to 4 decimal places. Or choose "no solution."
2 Answers
- 8 years agoFavorite Answer
Combine logs:
log ((x-5)(x+2)) = log (x+3)
So (x-5)(x+2) = (x+3)
x² - 3x - 10 = x + 3
x² - 4x - 13 = 0
(x-2)² = 13 + 4
x - 2 = ±√17
x = 2 ± √17
Cannot take log of negative numbers, so x - 5 > 0 is a requirement.
This means x = 2 + √17 = 6.1231
- RogueLv 78 years ago
log (x-5) + log (x+2) = log (x+3)
give log(a) + log(b) = log(ab)
=> log((x-5)(x+2)) = log (x+3)
=> (x-5)(x+2) = x +3
=> x^2 -3x -10 = x + 3
=> x^2 -4x = 13
=> x^2 -4x + 4 = 17
=> (x - 2)^2 = 17
=> x -2 = 屉17
=> x = 2屉17
as 2-â17 will result in a log of a negative number in the original question it not a valid solution.
=> x = 2+â17
=> x = 6.1231 (4 dp)