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? asked in Science & MathematicsMathematics · 8 years ago

Solve the following logarithmic equation.?

log (x-5) + log (x+2) = log (x+3)

Round off answer to 4 decimal places. Or choose "no solution."

2 Answers

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  • 8 years ago
    Favorite Answer

    Combine logs:

    log ((x-5)(x+2)) = log (x+3)

    So (x-5)(x+2) = (x+3)

    x² - 3x - 10 = x + 3

    x² - 4x - 13 = 0

    (x-2)² = 13 + 4

    x - 2 = ±√17

    x = 2 ± √17

    Cannot take log of negative numbers, so x - 5 > 0 is a requirement.

    This means x = 2 + √17 = 6.1231

  • Rogue
    Lv 7
    8 years ago

    log (x-5) + log (x+2) = log (x+3)

    give log(a) + log(b) = log(ab)

    => log((x-5)(x+2)) = log (x+3)

    => (x-5)(x+2) = x +3

    => x^2 -3x -10 = x + 3

    => x^2 -4x = 13

    => x^2 -4x + 4 = 17

    => (x - 2)^2 = 17

    => x -2 = ±√17

    => x = 2±√17

    as 2-√17 will result in a log of a negative number in the original question it not a valid solution.

    => x = 2+√17

    => x = 6.1231 (4 dp)

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