Biology X linked dominant?

None of his sons will have the disorder and all of his daughters will be affected.

This is because sons get 1 X from their mother and 1 Y from their father.

The disease is in the X chromosome, so getting Y from the father is fine.

Daughters have 1 X from their mother and 1 X from their father.

Since the disease is X linked and the father only has XY, the only X he can give is a diseased one. The disease is dominant, so even paired with a healthy X from the mother, all the girls will be affected.

in this case you would make a punnet square. put xx on one side for the mom, and xy (make some kind of mark on the x because its affected). if you solve the square, you will see that 100% of the daughters are affected because the x from the dad is dominant. it affects 0% of the sons because the mom doesnt carry the disorder and the sons get the dad's y chromosome but not x as it comes from the mom.

hope this helped, and was clear to understand haha

All his daughters will become carriers of the disorder (they will have a 50% chance to make their sons infected and 50% chance to make their daughters carriers as well), and all his sons will become homozygous dominant (unaffected by the disease), as the male gives the Y chromosome to his son, which is not sex linked to the disorder.

There is more chance to affecting this disorder to daughter,hence the daughter get x from his father. But son has no problem with this, Because he get an x from his mother..

(The reason- Male have XY chromosome and female have XX chromosome.So Female gets one x from her father and other from her mother. Male get x from his mother and Y from his father.)