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Find the molecular formula for estriol?

Combustion analysis of a 13.42 g sample of estriol (which contains only carbon, hydrogen, and oxygen) produces 36.86g CO2 and 10.06g H2O. The molar mass of estriol is 288.38g/mol .

I know the answer is C18H24O3. But I actually want to know how to do this problem. Thanks

1 Answer

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  • Bobby
    Lv 7
    8 years ago
    Favorite Answer

    we use the mass of carbon dioxide to work out the mass of carbon

    molar mass of CO2 = 44 g/ mole

    36.86 g of CO2 has 36.860 /44 = 0.83773 moles of CO2

    there is 1 mole of C in CO2 and all the C from the compound becomes CO2

    so moles of C in the compound = 0.83773 moles

    mass of C = 0.83773 x 12 = 10.06697 g

    we use the mass of water to find out the mass of hydrogen

    molar mass of H2O = 18 g/ mole

    10.06 g of H2O has 10.0600 / 18 = 0.55842 moles of H2O

    there are 2 moles of H in H2O so moles of H in the compound = 1.11683 moles

    mass of H = 1.11683 x 1.0079 = 1.1257 g

    we calculate the O by difference from the mass of sample once we know the mass of C and H

    mass of H + C = 11.19263 g

    mass of sample = 13.420 g

    mass of O by difference = 2.22737 g

    moles of O = 2.22737 /16 = 0.13921 moles

    we now work out the molar ratio of all the elements in the compound

    molar ratio of C : H : O = 0.83773 : 1.11683 : 0.13921

    smallest number 0.13921

    divide the ratio by the smallest number we get

    molar ratio of C : H : O = 6.0 : 8.0 : 1.0

    empirical formula is C6H8O

    this has a formula mass of 72+8+16 = 96g

    to find the number of empirical units in a mole of compound we divide the molar mass by the formula mass

    = 288.38 / 96 = 3.0

    so the molecular formula of estriol is 3 x the empirical formula or C18H24O3

    there is your solution ..

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