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- 8 years agoFavorite Answer
(9!)^(1/9) and (10!)^(1/10)
Raise them both to the 90th power
(9!)^10 and (10!)^9
(9!)^10 =.= (10 * 9!)^9
(9!)^10 =.= 10^9 * (9!)^9
9! =.= 10^9
We can tell, intuitively, that 9! < 10^9. Therefore, (9!)^(1/9) < (10!)^(1/10)
- 8 years ago
ninth root of 9! = 4.14716627...
tenth root of 10! = 4.52872868...
∴ninth root of 9! < tenth root of 10!
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