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Combinatorics question?

How many different three digit positive integers are there? (No leading zeroes are

allowed.) How many positive integers with at most three digits? What are the

answers when “three” is replaced by “n?”

1 Answer

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  • ?
    Lv 7
    8 years ago
    Favorite Answer

    It will look like _ _ _. The first digit has 9 choices (1-9). For each of those, the second digit has 10 choices (0-9) and the same for the third digit. So there are 9 * 10^2 three digit positive integers.

    At most 3 means it could have 1, 2, or 3 digits. That's all the integers from 1-999. So it is 999 = 10^3 - 1.

    With n, question 1 becomes 9 * 10^(n-1).

    Question 2 is 10^n - 1.

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