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Combinatorics question?
How many different three digit positive integers are there? (No leading zeroes are
allowed.) How many positive integers with at most three digits? What are the
answers when “three” is replaced by “n?”
1 Answer
- ?Lv 78 years agoFavorite Answer
It will look like _ _ _. The first digit has 9 choices (1-9). For each of those, the second digit has 10 choices (0-9) and the same for the third digit. So there are 9 * 10^2 three digit positive integers.
At most 3 means it could have 1, 2, or 3 digits. That's all the integers from 1-999. So it is 999 = 10^3 - 1.
With n, question 1 becomes 9 * 10^(n-1).
Question 2 is 10^n - 1.