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Combinatorics problem?
We want to know how many ways 3 boys and 4 girls can sit in a row.
(a) How many ways can this be done if there are no restrictions?
(b) How many ways can this be done if the boys sit together and the girls sit
together?
(c) How many ways can this be done if the boys and girls must alternate?
1 Answer
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- M3Lv 78 years agoFavorite Answer
a. 7P7 = 7! = 5040 <-----
b. [boys-girls or girls-boys], so 2*3!*4! = 288 <----
c. only pattern possible is gbgbgbg, so 3!*4! = 144 <------
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