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help with the second and third part of this question?
i just need some help with part B and C because im not sure how to do either, thank you! if you show your work so i can follow along and figure out how to solve it that would be awesome!
1 Answer
- mecdubLv 78 years agoFavorite Answer
ΔH reaction = Σ ΔH bonds broken - Σ ΔH bonds formed
One H-H bond and on I-I bond is broken, so Σ ΔH broken = 436 + 151.
Two H-I bonds are formed, so Σ ΔH formed = 2(299).
ΔH = 436 + 151 - 2(299)
= 587 - 598
= -11 kJ/mol.
To make the profile, put the reactants above the products, since the reaction is exothermic, and fill in the energy changes.
