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help with math questions?
Perform the following division (find the quotient).
(45 x^2 - 9 x^3 - 18 x^4) / (-18 x^3)
Simplify. Write the answer with positive exponents only.
(5 x^5 y^5)\(9 x^3 y**3))/(15 x y^5)(3 x y^9)
2 Answers
- Anonymous8 years ago
"Given 1)(45 x^2 - 9 x^3 - 18 x^4) / (-18 x^3)
=>(2x^2+x-5)/2x
….....x +1/2
…...----------------
...2x| 2x^2+x-5
…....2x^2
…....--------
…..........x
…..........x
….......------
….........-5
hence the reminder = -5
and quotient =x+1/2
2)(5 x^5 y^5)/(9 x^3 y^3))/(15 x y^5)(3 x y^9)
=>(x^2y^6)/9
and if the question is
(5 x^5 y^5)/(9 x^3 y^3))/[(15 x y^5)(3 x y^9)]
=>1/(81y^12)"
Source(s): Dividing Exponents - http://math.tutorvista.com/number-system/dividing-... - Anonymous8 years ago
(45 x^2 - 9 x^3 - 18 x^4) / (-18 x^3)
Sorry I don't know how to format the string below so that it would look properly in the long division.
x + 1/2
|-----------------------------------
-18x3 | -18x^4 - 9x^3 + 45x^2
-18x^4 - 0x^3
------------------------------------
- 9x^3 + 45x^2
- 9x^3 + 0x^2
------------------------------------
45x^2
(5 x^5 y^5)\(9 x^3 y**3))/(15 x y^5)(3 x y^9) = 1/81y^12