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Ahockey goalie is standing on ice. Another player fires a puck (m = 0.21 kg) at the goalie with a velocity of?
A hockey goalie is standing on ice. Another player fires a puck (m = 0.21 kg) at the goalie with a velocity of +66 m/s
(a) If the goalie catches the puck with his glove in a time of 6.0 X 10^-3 s, what is the average force (magnitude and direction) exerted on the goalie by the puck?
2310 N
(b) Instead of catching the puck, the goalie slaps it with his stick and returns the puck straight back to the player with a velocity of −66 m/s. The puck and stick are in contact for a time of 6.0 X 10^-3 s. Now what is the average force exerted on the goalie by the puck?
The answer is in N, i keep getting -4620 but its wrong, I got part A correct though.
1 Answer
- 8 years agoFavorite Answer
(a) By the impulse-momentum theorem
Ft = Δ(mv) = m(vf - vi)
then
F = m(vf - vi)/t = 0.21 (0 - 66) / (6.0x10^-3) = - 2310 N (and not 2310)
(b) By the same equation:
F = m(vf - vi)/t = 0.21 (- 66 - 66) / (6.'x10^-3) = - 4620 N
Your answer seems quite correct: what does the book say instead?
