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What's a stable structure for C9H10O3 given the IR and NMR data below?
IR: 2300-3200, 1710, 1600;
H1-NMR: 2.9--2H--triplet, 4.1--2H triplet, 6.9--3H--(crazy quartet looking), 7.1--2H--(crazy triplet looking), 11.7--1H--singlet/broad.
I think that is a 1,4-disubstituted benzene ring (C6H4) based on the two triplets at 2.9 and 4.1 and that there's a COOH group somewhere, given the IR. The crazies around 7 are screwing with my head. I've been doing fairly well with this NMR stuff otherwise :(
Please help with the rest of the problem!
Actually, come to think of it, I don't think it's a 1,4-disubstituted benzene ring since that has 2 doublets not 2 triplets...
4 Answers
- Anonymous7 years agoFavorite Answer
It's a monosubstituted benzene ring, with C6H5-O-CH2-CH2-COOH.
The two triplets are the CH2 groups, and the craziness is from the coupling on the benzene ring. Their values are more consistent with ring-H, whereas the 2.9 and 4.1 values are more consistent with CH2 groups that are heavily deshielded by electronegative atoms (the oxygens).
Hope that helps!
Source(s): I had this problem too. - 6 years ago
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What's a stable structure for C9H10O3 given the IR and NMR data below?
IR: 2300-3200, 1710, 1600;
H1-NMR: 2.9--2H--triplet, 4.1--2H triplet, 6.9--3H--(crazy quartet looking), 7.1--2H--(crazy triplet looking), 11.7--1H--singlet/broad.
I think that is a 1,4-disubstituted benzene ring (C6H4) based on the two triplets at 2.9 and 4.1 and that there's a COOH group...
Source(s): 39 stable structure c9h10o3 ir nmr data below: https://tr.im/8TBzr - Anonymous5 years ago
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This looks like 2-bromo-2-pentene. Can't tell from the information given whether it's E or Z.