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Algebra 2 question, what is the value of z in the system of equations?

2x-y=-5

4x+4y-2z=-6

4x+3z=6

1 Answer

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  • 7 years ago

    2x - y = -5

    4x + 4y - 2z = 6

    4x + 3z = 6

    All of these equations have an x in them, so solve the first and third equations for their OTHER variable:

    2x - y = -5

    -y = -2x - 5

    y = 2x + 5

    4x + 3z = 6

    3z = -4x + 6

    z = (-4/3)x + 2

    Plug these into the middle equation:

    4x + 4(2x + 5) - 2((-4/3)x + 2) = -6

    Now everything is in terms of x. Expand and simplify to solve for x:

    4x + 8x + 20 + (8/3)x - 4 = -6

    (44/3)x + 16 = -6

    (44/3)x = -22

    x = -22 * (3/44) = -3/2

    Now that we have x, plug this into the third equation we re-wrote to find z:

    z = (-4/3)(-3/2) + 2

    Simplify:

    z = 2 + 2 = 4

    So, z = 4

    Source(s): BA in Mathematics
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