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can someone please help me with this math problem?
The perimeter of a rectangle is 108 ft. The length is six more than twice the width. Find the length
3 Answers
- 7 years ago
A rectangle has 4 sides. (Which is why each is doubled below.)
Width = x
Length = 2x + 6
2x + 2(2x+6) = 108
2x + 4x + 12 = 108
6x + 12 = 108
6x = 96
x = 16
Therefore:
Width = 16
Length = 38
Proof:
2(16) + 2(38)
32 + 76 = 108
- MarianneLv 67 years ago
2L + 2W = 108
L + W = 54
Length = 2W + 6
2W + 6 + W = 54
3W + 6 = 54
3W = 48
W = 16
If the width is 16, then 2W + 6 = 38.
38 + 38 + 16 + 16 = 108
