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Physics Help! Rigid Body rotation?
A 790g , 46-cm-long metal rod is free to rotate about a frictionless axle at one end. While at rest, the rod is given a short but sharp 1000 N hammer blow at the center of the rod, aimed in a direction that causes the rod to rotate on the axle. The blow lasts a mere 2.5ms.
I know the answer is approximately 10 rad/s, but could somebody please explain it to me?
1 Answer
- SteveLv 77 years agoFavorite Answer
I = (1/3)mL² = (1/3)*0.790*(0.46)² = 0.05572 kg∙m²
Angular impulse P = F*t*R = 1000*2.5E-3*0.23 = 0.575 N∙s∙m
dw = P/I = 10.32 rad/sec
