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lottery odds/ cards...................................?
I'm trying to create an equal probability with choosing from a standard 52 playing cards deck. How Many cards would you have to guess in advance in order to equal the odds of picking the lottery winners (1/259 million?)
Ty Hi. What about picking them all at once before turning any over?
And in exact order.
1 Answer
- 7 years agoFavorite Answer
About 5.
I interpreted your question this way: Draw a card face down from a deck if cards, and correctly guess which card it is. Repeat. What is the probability of guessing correctly n times?
Without replacement: If you take a card, make your guess, and then set that card aside before drawing another card, then the probability of getting FIVE correct is
(1/52) * (1/51) * (1/50) * (1/49) * (1/48) = 1/311875200 (about one in 312 million).
With replacement: If you take a cards make your guess, and put the card back in the deck an shuffle it before drawing another card, then the probability of getting FIVE correct is
(1/52) ^ 5 = 1/380204032 (about 1 in 380 million).
Selecting four cards wouldn't be nearly close enough.