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Given two independant events, A and B, show that P(A|B complement) = P(A)?

Given two independant events, A and B, show that P(A|B complement) = P(A)

I can visualize this pretty easy, just can't put it on paper. Thanks

3 Answers

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  • Anonymous
    7 years ago
    Favorite Answer

    P(A n B' ) = P(A) - P(A n B) = P(A) - P(A)P(B) = P(A)[1 - P(B)]=P(A)P(B' )

    ---> A and B' is independent events ---> P(A|B' ) = P(A)

  • 7 years ago

    P ( A ) = P ( B ) P ( A I B )

    P ( B ' ) = 1 - P ( B )

    P ( B ) = 1 - P ( B ' )

    you can do the substitutions.

    Source(s): my brain
  • ?
    Lv 7
    7 years ago

    b' is independent of a so by definition, p(a|b') is p(a)

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