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Java programming algorithm?
Below is a program that I wrote but I kind of don;t get one thing. I put a while loop in the beginning, and pretty much it says that while response's first character is y, then the program will run. I don;t quite understand then why the program initially runs, if the whole condition is WHILE response's first character is y, THEN the program will run. I am fairly new at this so be kind, thank you!
import java.util.Scanner;
public class methods {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String response = "yes";
while(response.charAt(0)=='y'){
System.out.println("Enter password:");
String answer;
answer = input.nextLine();
System.out.println("That's" + " " + answer.equalsIgnoreCase("Noah") + ",");
System.out.println("do you wish to try again?");
response = input.nextLine();
}
}
}
1 Answer
- 7 years agoFavorite Answer
I do not know java, but I think I can help you.
You have String response="yes"; So the first character of Response is set to 'y'.
while (response.charAt(0)=='y' must check the first character or response, which is 'y'. So you will enter the loop.
At the end of the loop, you ask for a new value if response. If the first character is 'y', it will loop, otherwise the loop will end.